Thanks for replying. On Sat, Dec 1, 2012 at 8:49 AM, Aaron Meurer <asmeu...@gmail.com> wrote: > > easy way to fix it is to use summation(t**i*Ra(i),(i,0,5)).doit().
Wow nice, that works! > Care to open an issue for this in our issue tracker > (https://code.google.com/p/sympy/issues/list)? I reported it here with your comments: https://code.google.com/p/sympy/issues/detail?id=3543 Note that I have made the subject to read "summation containing summation" but perhaps the actual bug is more widespread than that so please change the title if inappropriate or inaccurate. On Sat, Dec 1, 2012 at 8:30 AM, Shriramana Sharma <samj...@gmail.com> wrote: > print(summation(t**i*Ra(i),(i,0,5))) Curiously replacing 5 by n, i.e. as print(summation(t**i*Ra(i),(i,0,n))) gives the output: Sum(t**i*Sum((-1)**(i + j)*ival(j)*binomial(i, j)*binomial(n, i), (j, 0, i)), (i, 0, n)) so only when the actual finite evaluation is done does the problem surface. -- Shriramana Sharma -- You received this message because you are subscribed to the Google Groups "sympy" group. To post to this group, send email to sympy@googlegroups.com. To unsubscribe from this group, send email to sympy+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/sympy?hl=en.
