Maybe you want to use nested lambdas:
map(lambda c: lambda f: Diff(f,c), coords)
On Wednesday, April 17, 2013 10:11:14 PM UTC+2, brombo wrote:
>
> Consider the following
>
> coords = symbols('x,y,z')
>
> I wish to contruct the list of functions:
>
> [Dx,Dy,Dx]
>
> where
>
> def Dx(f):
> return(diff(f,coord[0]))
>
> etc.
>
> but I want to build the list [Dx,Dy,Dz] with a for loop and not have to
> do a separate
>
> def Dx(f):
> return(diff(f,coord[0]))
>
> def Dy(f):
> return(diff(f,coord[1]))
>
> def Dz(f):
> return(diff(f,coord[2]))
>
> since when I am writing the code I don't know how long coords will be.
>
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