Is this the same thing as the matrix derivative described in the
matrix cookbook (see
https://code.google.com/p/sympy/issues/detail?id=2759)?  If so, then
the answer is no.

Aaron Meurer

On Sun, Apr 21, 2013 at 7:28 AM, Saurabh Jha <saurabh.j...@gmail.com> wrote:
> Hi,
>
> I wanted to know if something like this is already implemented in
> sympy?
>
> for a function f: R(m × n)--> R mapping from mapping from m × n
> matrices(let's say A) to real numbers than,
>
> ∇Af(A) =[∂f/∂A(11).............∂f/∂A(1n) ]
>             [                                        ]
>             [                                        ]
>             [∂f/∂A(n1)..............∂f/∂A(nn)]
>
> Note: with ∇Af(A), I meant taking gradient of   f(A) with respect to
> matrix A and with ∂f/∂A(11), I meant taking derivative of function f
> with respect to element A(11)  of matrix A.
>
> -Saurabh Jha
>
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