Internally, there is no difference between 1/(x + 1)**2 and (x +
1)**-2. There is no class in SymPy that represents division. 1/x is
represented internally as just Pow(x, -1).
If all you care about is printing, then I recommend you modify the printer.
Which printer are you using? What you need to do is subclass the
appropriate printer and override the _print_Pow method.
Aaron Meurer
On Sun, Jun 16, 2013 at 11:40 PM, Ben Lucato <ben.luc...@gmail.com> wrote:
> If I have code like so:
>
> x = sympy.Symbol('x')
> y = 1 / (x + 1)**2
>
> it evaluates to
> y = (x + 1)**(-2)
>
>
> is there a way to prevent that happening and have it remain as 1 / (x +
> 1)**2.
>
> **** OR: alternatively, is there a way to retrieve 1 / (x + 1)**2 from the
> canonical form? I've looked at the docs and searched in this google group
> but haven't found relevant discussions. The reason I want to do this is for
> printing purposes
>
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