Hi, I just had the time to have a look at the issue. After reading it, I'm
inferring that performing subs on an unevaluated integral, should do the
same as what xreplace does
For example:
eq = Integral((exp(x*log(x))*log(x)), (x, 0, 1)).subs(exp(x*log(x)), x**x)
Integral(exp(x*log(x))*log(x), (x, 0, 1))
eq = Integral((exp(x*log(x))*log(x)), (x, 0, 1)).xreplace({exp(x*log(x)): x
**x})
Integral(x**x*log(x), (x, 0, 1))
eq = Integral(x, x).subs(x, y)
Integral(y, x)
eq = Integral(x, x).xreplace({x: y})
Integral(y, y)
I would like to know if my interpretation is right before working on the
issue. Thanks
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