Consider (F1) sqrt(1+x^3)/x (F2) sqrt(1+1/x^3)*sqrt(x)
According to Mathematica's online integrator (I1) integral F1 dx = (2/3)*(sqrt(x^3+1)-arctanh(sqrt(x^3+1))) (I2) integral F2 dx = (2*sqrt(1/x^3+1)*x^(3/2)*(sqrt(x^3+1)-arctanh(sqrt(x^3+1))))/(3*sqrt(x^3+1)) SymPy Live computes (I1) as (S) 2*x**(3/2)/(3*sqrt(1 + x**(-3))) - 2*asinh(x**(-3/2))/3 + 2/(3*x**(3/2)*sqrt(1 + x**(-3))) SymPy Live timed out with (I2). SymPy 0.7.3 computes (I2) as (S) 2*x**(3/2)/(3*sqrt(1 + x**(-3))) - 2*asinh(x**(-3/2))/3 + 2/(3*x**(3/2)*sqrt(1 + x**(-3))) The derivative of (S) is (F2) and not (F1). So I am inclined to say that SymPy computes (I1) not correctly. Peter -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sympy+unsubscr...@googlegroups.com. To post to this group, send email to sympy@googlegroups.com. Visit this group at http://groups.google.com/group/sympy. For more options, visit https://groups.google.com/groups/opt_out.
