On Saturday, November 2, 2013 11:46:27 AM UTC+1, Saullo Castro wrote:
>
> I believe we can make a variable transform and then apply the derivative 
> using the expression converted to a variable, like:
>
>     x = a**2 + c + d**3
>     x.diff((a + c**2))
>
> changing variables:
>
>     v = a + c**2
>     a = v - c**2
>     c = (v-a)**0.5
>
> the new x will be:
>
>     x2 = (v-c**2)**2 + (v-a)**0.5 + d**3
>
> and the derivative could be computed as:
>
>     x2.diff(v)
>
> is that reasonable?
>

Yes, it is.

Are you going to use .subs( ) or solve( ) ? 

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