Yep:
 
>>> (sinh(x)).replace(sinh, lambda arg: exp(arg)/2)exp(x)/2



On Thursday, October 31, 2013 6:14:59 PM UTC+4, Aaron Meurer wrote:
>
> Use replace to replace functions. 
>
> Aaron Meurer
>
> On Oct 31, 2013, at 6:48 AM, Boris Kheyfets <kheyf...@gmail.com<javascript:>> 
> wrote:
>
> I have a large argument, so I'd rather neglect exp(-x) in the definition 
> of sinh. How do I substitute sinh by 1/2*exp ?
>
> I tried .subs({sinh: 0.5*exp}) and .subs({2 * sinh: exp}) but it doesn't 
> work: TypeError: unsupported operand type(s) for *: 'int' and 
> 'FunctionClass'.
>  
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