Thanks for this.

2014-02-17 19:21 GMT+01:00 Avichal Dayal <avichal.da...@gmail.com>:

> However gruntz gives the correct result:-
> gruntz((x*exp(x)) / (exp(x)-1), x, -oo) gives 0
>
> The part of code that is going wrong is already labeled as XXX: todo
> More specifically the following:-
> if abs(z0) is S.Infinity:
>             # XXX todo: this should probably be stated in the
>             # negative -- i.e. to exclude expressions that should
>             # not be handled this way but I'm not sure what that
>             # condition is; when ok is True it means that the leading
>             # term approach is going to succeed (hopefully)
>
> It should exclude some expressions and I guess this is one of them.
> I'll try to understand and fix it.
>
>
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