I'd love to have someone implement matrix derivative.  This shouldn't be
hard for someone who understands them well.


On Mon, Apr 28, 2014 at 7:37 PM, Aaron Meurer <asmeu...@gmail.com> wrote:

> These little issues with the transpose are the reason this isn't
> implemented yet.
>
> Aaron Meurer
>
> On Mon, Apr 28, 2014 at 2:18 PM, Tim Lahey <tim.la...@gmail.com> wrote:
> > It's only 2*A*x is A is symmetric (A.T = A). Otherwise it's (A.T + A).
> That said, I don't think Matrix Expressions support derivatives at the
> moment.
> >
> > Cheers,
> >
> > Tim.
> >
> > On 2014-04-28, at 1:27 PM, Gustavo <gustavo.goret...@gmail.com> wrote:
> >
> >> Can I have matrices and vectors A and x with compatible but unspecified
> dimensions. And get diff(x.T * A * x , x) return 2*A*x ?
> >>
> >> Thanks,
> >> Gustavo
> >
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