On Friday, June 27, 2014 4:03:27 AM UTC-4, Camille Chambon wrote: > > Hello Chris, > Thanks a lot for your answer! It's very interesting. By now I just need > the bisection method: nsolve(eq,c2,(1,1000),solver='bisect'). But I will > keep in mind the continuation method for the future. > Cheers, > Camille >
If performance is an issue, you might want to consider the more advanced bisection methods, for instance `solve='illinois'` which combines the bisection method with the secant method. It converges much faster, but it is less robust. Vinzent -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sympy+unsubscr...@googlegroups.com. To post to this group, send email to sympy@googlegroups.com. Visit this group at http://groups.google.com/group/sympy. To view this discussion on the web visit https://groups.google.com/d/msgid/sympy/5e504ef0-774d-46ce-947b-e3748585e05f%40googlegroups.com. For more options, visit https://groups.google.com/d/optout.
