On Sunday, October 12, 2014 1:50:10 AM UTC+2, Aaron Meurer wrote: > > That's correct. If integrate() returns an unevaluated Integral, it > means the algorithm couldn't compute an integral. The fu() function is > able to simplify this expression (it equals 2*sin(x)), so > integrate(fu(fx), x) works. > > Why is fu( ) not attempted in the integrate( ) algorithm?
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