Consider this use case In [97]: expr = 1/(1-x) + 1/(1+x)
In [98]: e2 = Integral(expr, x) In [99]: e2 Out[99]: ⌠ ⎮ ⎛ 1 1 ⎞ ⎮ ⎜───── + ──────⎟ dx ⎮ ⎝x + 1 -x + 1⎠ ⌡ Suppose now I want to act on the expression inside the integral by applying *together* and *expand* on it, is there a simple way to do so? In [102]: expr.together().expand() Out[102]: 2 ──────── 2 - x + 1 More accurately, is there an easy way to select a subexpression, apply some transformations only on that subexpression, and returning the entire expression with the applied transformations? In this case one could extract the integral argument by *e2.args[0]*, and then rebuild *e2.func(new_arg_0, e2.args[1:])*, but imagine if the tree expression is much more complicated and it is hard/uncomfortable to select the subexpression by accessing the *args*, what can one do? -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sympy+unsubscr...@googlegroups.com. To post to this group, send email to sympy@googlegroups.com. Visit this group at http://groups.google.com/group/sympy. To view this discussion on the web visit https://groups.google.com/d/msgid/sympy/b59b0e08-884b-4d09-9065-d604f3509d5c%40googlegroups.com. For more options, visit https://groups.google.com/d/optout.
