What version of SymPy is this?

Aaron Meurer

On Sat, Feb 7, 2015 at 3:22 PM, Sten Sogaard <sten.soga...@gmail.com> wrote:

> I am trying to do an inverse laplace transformation of a relative simple
> filter, but have found that it does not take much before the transformation
> takes forever.
>
> I wonder if there is something wrong in my configuration.   Windows
> 7 WinPython-32bit-2.7.6.4
>
> I started to strip out terms in my filter to see when Sympy could compute
> a result.
>
> When I try just the real filter (last calculation), the memory footprint
> keeps growing. I stopped it at 2G.
>
> Any ideas
>
>
> from sympy import *
> from sympy.abc import s,t
> from datetime import datetime
>
> startTime = datetime.now()
> H = 1/(258.0*s + 1100000.)
> inverse_laplace_transform(1/s*H,s,t)
> print "1) ",datetime.now() - startTime                   * #my computer
> takes 0.3sec*
>
> startTime = datetime.now()
> H = 1/(0.07071*s**2 + 258.0*s + 1100000.)
> inverse_laplace_transform(1/s*H,s,t)
> print "2) ",datetime.now() - startTime                    *# 55 minutes
> and still no solution.... Memory usage: 50Meg*
>
> startTime = datetime.now()
> H = 1/(7.896e-6*s**3 + 0.07071*s**2 + 258.0*s + 1100000.)
> inverse_laplace_transform(1/s*H,s,t)
> print "3) ",datetime.now() - startTime
>
> #Real filter
> startTime = datetime.now()
> H = (0.05*s + 1000.0)**2/(2.209e-10*s**4 + 7.896e-6*s**3 + 0.07071*s**2 +
> 258.0*s + 1100000.)
> inverse_laplace_transform(1/s*H,s,t)
> print "4) ",datetime.now() - startTime
>
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