Thank you.
On Friday, March 27, 2015 at 9:55:21 PM UTC+2, Aaron Meurer wrote:
>
> It looks like Poly.from_dict will do it:
>
> In [6]: p = Poly(6*x**4*y**5 + 3*x*y**2,y,x)
>
> In [7]: p.as_dict()
> Out[7]: {(2, 1): 3, (5, 4): 6}
>
> In [8]: p.from_dict(p.as_dict(), y, x)
> Out[8]: Poly(6*y**5*x**4 + 3*y**2*x, y, x, domain='ZZ')
>
> The order of the generators is the same as the order in the Poly. I
> don't remember if there is a better method on Poly for reordering
> generators, but in the above example Poly(p, x, y) will reorder them.
>
> Aaron Meurer
>
>
> On Fri, Mar 27, 2015 at 2:50 PM, Paul Royik <distan...@gmail.com
> <javascript:>> wrote:
> > Suppose I have following polynomial:
> > poly= Poly(6*x**4*y**5 + 3*x*y**2,y,x)
> >
> > It's dictionary is
> > poly.as_dict() # {(5, 4): 6, (2, 1): 3}
> >
> >
> > How can I restore poly from dict?
> > How do I know that (5, 4) - > (y, x) ?
> > poly.free_symbols is set, so it is unordered.
> >
> > Is there any way to fetch that from Poly?
> >
> > One way I think is following:
> >
> > variables = [x,y]
> > poly= Poly(6*x**4*y**5 + 3*x*y**2,variables)
> >
> > #(5, 4) - > variables
> >
> >
> > And next question: how are coeffcients are ordered? Can I change order?
> > order keyword throws exception...
> >
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