Got it: As outlined in [1], what is mathematically perceived as a "function" is a class in terms of sympy, not an instance thereof.
--Nico [1] http://docs.sympy.org/latest/modules/functions/index.html On Thursday, July 16, 2015 at 9:53:17 AM UTC+2, Nico wrote: > > Following up on question [1], I'm wondering how one can derive from > sympy.Function in a way that keeps all the original functionality in place. > Something as naive as > ``` > import sympy > > x = sympy.Symbol('x') > > a = sympy.Function('a') > a(x) # no problem > > class MyTest(sympy.Function): > pass > b = MyTest('b') > b(x) # object is not callable > ``` > doesn't work: `b` is reported not to be callable here. > > Any hints why this might be and how to fix it? > > Cheers, > Nico > > > [1] https://groups.google.com/forum/#!topic/sympy/5mLEq4Gbyfk > -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sympy+unsubscr...@googlegroups.com. To post to this group, send email to sympy@googlegroups.com. Visit this group at http://groups.google.com/group/sympy. To view this discussion on the web visit https://groups.google.com/d/msgid/sympy/57e9ce21-26d0-4bee-a505-7480ed4fd506%40googlegroups.com. For more options, visit https://groups.google.com/d/optout.
