It's worth pointing out that computing this integral is very likely going
to require the algebraic Risch algorithm. Maybe a pattern matching case for
it can be added to something like Rubi or manulaintegrate (I'm actually
curious if Rubi can do this), but the solution, at least as Sage has
presented it, looks rather complicated (e.g., the fact that the result has
logarithms means that pattern matching integrators are going to be limited
without at least *some* Risch algorithm).

Aaron Meurer

On Thu, Jul 23, 2015 at 2:42 PM, Aaron Meurer <[email protected]> wrote:

> I think it is correct, at least algebraically:
>
> In [6]: a = S("-1/12*(3*(sqrt(x) + 1)^(5/2)/x^(5/4) - 8*(sqrt(x) +
> 1)^(3/2)/x^(3/4) - 3*sqrt(sqrt(x) + 1)/x^(1/4))/((sqrt(x) + 1)^3/x^(3/2) -
> 3*(sqrt(x) + 1)^2/x + 3*(sqrt(x) + 1)/sqrt(x) - 1) + 1/8*log(sqrt(sqrt(x) +
> 1)/x^(1/4) + 1) - 1/8*log(sqrt(sqrt(x) + 1)/x^(1/4) - 1)")
>
> In [7]: print(simplify(a.diff(x)))
> x**(1/4)*sqrt(sqrt(x) + 1)
>
> (if you distribute sqrt(sqrt(x)) inside the sqrt(sqrt(x) + 1) you get
> sqrt(x + sqrt(x))
>
> Aaron Meurer
>
> On Thu, Jul 23, 2015 at 2:37 PM, Kalevi Suominen <[email protected]> wrote:
>
>>
>>
>> On Thursday, July 23, 2015 at 8:31:41 PM UTC+3, Denis Akhiyarov wrote:
>>>
>>> Sympy cannot do this?
>>>
>>> integrate(sqrt(x+sqrt(x)))
>>>
>>> BTW, this is computed by SAGE:
>>>
>>> -1/12*(3*(sqrt(x) + 1)^(5/2)/x^(5/4) - 8*(sqrt(x) + 1)^(3/2)/x^(3/4) -
>>> 3*sqrt(sqrt(x) + 1)/x^(1/4))/((sqrt(x) + 1)^3/x^(3/2) - 3*(sqrt(x) + 1)^2/x
>>> + 3*(sqrt(x) + 1)/sqrt(x) - 1) + 1/8*log(sqrt(sqrt(x) + 1)/x^(1/4) + 1) -
>>> 1/8*log(sqrt(sqrt(x) + 1)/x^(1/4) - 1)
>>>
>>
>>
>> I Is it possible to verify that this really is a solution. The integrand
>> seems to belong to an elliptic function field where integration rarely
>> succeeds in terms of algebraic expressions.
>>
>>
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