I've just started learning Sympy. I wrote a few lines of code to perform a inverse laplace transform on a simple 2nd order transfunction:
H(s) = 1 / ((s+p1) * (s+p2)). The result I got from Sympy is (e^(p1*t) - e^(p2*t))*e^-t*(p1+p2) / (p1 - p2) Is there a way to simplify this result to the one like in Maxima (e^-t*p1 + e^-t*p2) / (p1-p2) ? -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sympy+unsubscr...@googlegroups.com. To post to this group, send email to sympy@googlegroups.com. Visit this group at https://groups.google.com/group/sympy. To view this discussion on the web visit https://groups.google.com/d/msgid/sympy/0b4a638b-b9d8-426d-99c3-12fdaf1cc973%40googlegroups.com. For more options, visit https://groups.google.com/d/optout.
