I had the same idea earlier, but i dropped it because my intuition was, 
that three quadratic equations are worse than three linear and one 
quadratic equation :-)

Since you brought this approach up again, i tried it now, but sympy does 
not seem to find a solution.

You can check out my code here: http://pastebin.com/famnqkLC

You wrote you expected sympy to find a solution for numeric coefficients, 
but i need a symbolic solution because i want to proceed further (by 
differentiating with respect so some of the parameters for optimization), 
and don't want a sympy.solve step in each optimization step.

Any idea why my original approach "explodes" in regards of the resulting 
expressions?


On Monday, June 13, 2016 at 12:48:30 AM UTC+2, Oscar wrote:
>
> On 11 June 2016 at 17:52,  <janosc...@gmail.com <javascript:>> wrote: 
> > 
> > Yes, exactly, its the linear bearings that can be at different locations 
> and 
> > force therefore the board to different positions, those are the ones 
> that i 
> > am interested in! 
>
> Rather than thinking about x, y and theta think about the three pin 
> positions. Give them position vectors r1, r2 and r3. Each is 
> constrained by a linear bearing and so e.g. r1 = a1 + t1*b1 where a1 
> and b1 are known vectors and t1 is the unknown line parameter. We have 
> then three unknown scalars t1, t2, and t3. Although we don't know r1, 
> r2, or r3 we do know their pairwise distances d12, d13 and d23. This 
> gives three equations e.g. |r1-r2|**2 = d12**2. Substitute for r1, r2 
> and r3 into those and we get 3 bivariate quadratic equations for t1, 
> t2, and t3. I would expect that sympy can solve that quickly for 
> numeric coefficients (if you can give numeric values for a1, b1, d12, 
> etc.). 
>
> In your example it's clear from symmetry that if phi is a solution 
> then so is phi+pi so you should expect to get multiple solutions here. 
> This method will also give upside down solutions that you may need to 
> prune. Presumably also you'll need to check the solutions for 
> consistency with the limits on the line bearings. 
>
> -- 
> Oscar 
>

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