Thank you. On Friday, January 17, 2020 at 10:34:39 PM UTC+2, Aaron Meurer wrote: > > There is still limited support for this, but you can use refine(expr, > Q.positive(x - 2)). Actually, if all you want to do is simplify all > roots in an expression you can use powdenest() and powsimp() with the > force=True flag. > > Aaron Meurer > > On Fri, Jan 17, 2020 at 12:26 PM Paul Royik <distan...@gmail.com > <javascript:>> wrote: > > > > I know that variables can be made positive or negative. > > > > But how do I make assumption that x>2? > > > > If I have and expression like (x-2)^(1/3)+(x-5)^(1/3) (actually > arbitrary expressions), how to make assumptions that all expressions under > roots are positive, i.e. x-2>0, x-5>0? > > > > -- > > You received this message because you are subscribed to the Google > Groups "sympy" group. > > To unsubscribe from this group and stop receiving emails from it, send > an email to sy...@googlegroups.com <javascript:>. > > To view this discussion on the web visit > https://groups.google.com/d/msgid/sympy/9edf1f7c-224d-4bf2-ba17-eea773465bb2%40googlegroups.com. > > >
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