How can I get a single solution of a diophantine equation when the solution is returned in terms of independent parameters?
>>> from sympy.abc import x, y, z, t >>> from sympy import diophantine, Symbols >>> diophantine(x + y + z, t) {(t_0, t_1, -t_0 - t_1)} >>> x, y, z = _.pop() Substitution does not work: >>> t_0, t_1 = Symbols('t_0 t_1') >>> x.subs(t_0, 1) t_0 >>> y.subs(t_1, 1) t_1 >>> z.subs({t_0: 1, t_1: 1}) -t_0 - t_1 Thanks Faisal Riyaz -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sympy+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/sympy/CAEe-xqTSsGgc4a55jKYmn-52L7%2BoqXGZWizEP5zEOvWDg8NVnw%40mail.gmail.com.