>>> ndec = lambda x: 0 if '.' not in str(x) else
len(str(x).split('.')[1].split('e')[0])
>>> (1, 1.0, 1.23, 1.234e-5, 3e5, 3e33)
(1, 1.0, 1.23, 1.234e-05, 300000.0, 3e+33)
>>> [ndec(i) for i in _]
[0, 1, 2, 3, 1, 0]
(Note that this is not the same thing as the number of significant digits.
And if you don't want to count trailing 0s then change `[0]` to
`[0].rstrip('0')`)
/c
On Friday, April 16, 2021 at 5:23:17 AM UTC-5 distan...@gmail.com wrote:
> How do I make sure that str() doesn't return exponential notation?
>
> On Friday, April 16, 2021 at 11:43:22 AM UTC+3 asme...@gmail.com wrote:
>
>> In that case, I think the simplest option would be to parse
>> str(float). Some split() and strip() operations should get you want
>> you want, or just use a regex.
>>
>> Aaron Meurer
>>
>> On Thu, Apr 15, 2021 at 11:56 PM Paul Royik <distan...@gmail.com> wrote:
>> >
>> > One digit. Ignore scientific notation.
>> >
>> > On Friday, April 16, 2021 at 1:23:53 AM UTC+3 asme...@gmail.com wrote:
>> >>
>> >> How would you count small numbers like 1.1e-30. Is that 1 digit or 31
>> >> digits after the decimal?
>> >>
>> >> Aaron Meurer
>> >>
>> >> On Thu, Apr 15, 2021 at 2:31 PM Paul Royik <distan...@gmail.com>
>> wrote:
>> >> >
>> >> > Rational(1,2).evalf(), how do I get 1 here (since 0.5 has 1 digit
>> after the dot)?
>> >> >
>> >> > --
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