I suppose you are referring to R4.50000000. This is a way to extract the forces/moments from the above equation:
fs = list(b.load.free_symbols) R45, R0, M0 = fs[1:] M0, R0, R45 Now you can create a substitution dictionary and compute the load at a given location. Davide. Il giorno lun 5 lug 2021 alle ore 15:11 shashank singh < singhvikramshash...@gmail.com> ha scritto: > from sympy import * > from sympy.physics.continuum_mechanics.beam import Beam > E, I = symbols('E, I') > b = Beam(9, E, I) > b.apply_load(-12, 9, -1) > b.apply_load(-50, 5, -2) > b.apply_load(-8, 0, 0, end=5) > b.apply_support(0, type='fixed') > b.apply_support(4.5, type='roller') > b.load > > after adding the above load i am getting the following equation > > 𝑀0⟨𝑥⟩−2+𝑅0⟨𝑥⟩−1+𝑅4.50000000000000⟨𝑥−4.5⟩−1−8⟨𝑥⟩0−50⟨𝑥−5⟩−2+8⟨𝑥−5⟩0−12⟨𝑥−9⟩−1 > > how i am supposed to find the reaction forces with those trailing zeros? > please help > > -- > You received this message because you are subscribed to the Google Groups > "sympy" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to sympy+unsubscr...@googlegroups.com. > To view this discussion on the web visit > https://groups.google.com/d/msgid/sympy/06ce7fab-256d-4a6f-bfdf-b2498002c9b2n%40googlegroups.com > <https://groups.google.com/d/msgid/sympy/06ce7fab-256d-4a6f-bfdf-b2498002c9b2n%40googlegroups.com?utm_medium=email&utm_source=footer> > . > -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sympy+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/sympy/CAO%3D1Z0--ahbhRVCGAeYAwVh27eSZ5hkf%3DCCaPRF3LVmGEMCdNA%40mail.gmail.com.