I am exploring ways to implement an Interval that will contain infinite boundaries. I am under the assumption that we can't make `Interval(-oo, oo)` mean `[-oo, oo]`.
Currently the default is to *automatically* exclude them, so `Interval(1, oo)` means `[1, oo)`. My idea is to use another keyword to allow for infinities to be included, like ``Interval(1, oo, ext=True)` to get [1, oo]. The interval `(1,oo)` is already entered as `Interval.Lopen(1, oo)`; to make it close on the right would require `Interval.Lopen(1, oo, ext=True)`. But that doesn't look very good. A more compact way to do this (and give an alternative to the functional, but not compact method, of giving 4 arguments) would be to use 2 letters to indicate closed or open status: Interval.cc(3,4) = [3,4] Interval.co(3,4) = [3,4) Interval.oc(3,4) = (3,4] Interval.oo(3,4) = (3, 4) Lopen and Ropen could be deprecated (or kept as legacy) but the printing could be done in terms of c and o. The problem with those two letters is that they look so much alike. underscore and "L" could be used as Interval.LL(3,4) = [3,4] Interval.L_(3,4) = [3,4) Interval._L(3,4) = (3,4] Interval.__(3,4) = (3, 4) Or "x" and "o" /c -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sympy+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/sympy/7e8d8218-32d4-4682-af22-20a47792b48dn%40googlegroups.com.
