Peter,
All `dynamicsymbols` is, is:
f = Function('f')
t = symbols('t')
f_of_t = f(t)
The last line `f(t)` is generating a new class of type f, instead of using
a predefined class (look up metaclasses). So the user, typically not aware
of this element in Python, is confused about what they are working with in
the last line. It is just the way SymPy Function works. There are open
issues about trying to change it to something more sensible for the user to
understand.
Jason
moorepants.info
+01 530-601-9791
On Sun, Feb 6, 2022 at 7:39 AM Peter Stahlecker <peter.stahlec...@gmail.com>
wrote:
> My question is more for my ‚general education‘ in sympy.
>
> I write this little program
>
> *from sympy.physics.mechanics import **
> *import sympy as sm*
> *a = dynamicsymbols(‚a‘)*
> *b = sm.symbols(‚b‘)*
>
> *print(‚type of a:‘, type(a))*
> *print(‚type of b:‘, type(b))*
>
> I get this result:
>
> *type of a: a*
> *type of b: class sympy.core.symbols.Symbols*
>
> Is seems that *a* does not have a type. How can that be? I thought in
> python ‚everything‘ has a type.
>
> Thanks!
> Any explanation is highly appreciated!
>
>
>
>
> --
> You received this message because you are subscribed to the Google Groups
> "sympy" group.
> To unsubscribe from this group and stop receiving emails from it, send an
> email to sympy+unsubscr...@googlegroups.com.
> To view this discussion on the web visit
> https://groups.google.com/d/msgid/sympy/5db2836e-44a8-428f-8b82-c56b2b2b5b20n%40googlegroups.com
> <https://groups.google.com/d/msgid/sympy/5db2836e-44a8-428f-8b82-c56b2b2b5b20n%40googlegroups.com?utm_medium=email&utm_source=footer>
> .
>
--
You received this message because you are subscribed to the Google Groups
"sympy" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to sympy+unsubscr...@googlegroups.com.
To view this discussion on the web visit
https://groups.google.com/d/msgid/sympy/CAP7f1Ajkjs%3DNhJOhrFXmEpLJ6nv0TM9FgHXg%3DS1kSCF-6Cw5zw%40mail.gmail.com.
