When I differentiate the function ψ = exp(I*(k*x))
I get i*k*exp(I*(k*x)). [which is i*k*ψ] Is there a way to get exp(I*(k*x)) substituted with ψ, in order to get the shorter expression i*k*ψ ? Thanks, André -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sympy+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/sympy/6f59ce08-aa7b-4f1b-8f7c-ce719a8770een%40googlegroups.com.
