Le mardi 23 mai 2023 à 21:26:20 UTC+2, asme…@gmail.com a écrit :
On Tue, May 23, 2023 at 7:21 AM Oscar Benjamin <oscar.j....@gmail.com> wrote: On Tue, 23 May 2023 at 06:51, Paul Royik <distan...@gmail.com> wrote: > > How do I simplify the following expressions: i**(-2*i), (-i)**(-2*i), ((-sqrt(3) - i)/2)**(-2*i), ((sqrt(3) - i)/2)**(-2*i) ? > > Is there any built-in function? > > For example, i**(-2*i) should give e^pi and ((sqrt(3) - i)/2)**(-2*i) should give e^(-pi/3). The word "simplify" is ambiguous but I assume from your examples that In this case, there's a fairly unambiguous meaning for 'simplify'. The expressions are all real, so they should be reexpressed without using i. Oh yeah ? Wait… <https://en.wikipedia.org/wiki/Casus_irreducibilis> Aaron Meurer what you want is to rewrite powers as exponentials if possible. If so that can be done with e.rewrite(exp): >>> from sympy import * >>> i = I >>> a = i**(-2*i), (-i)**(-2*i), ((-sqrt(3) - i)/2)**(-2*i), ((sqrt(3) - i)/2)**(-2*i) >>> [ai.rewrite(exp) for ai in a] [exp(pi), exp(-pi), exp(-5*pi/3), exp(-pi/3)] -- Oscar -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sympy+un...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/sympy/CAHVvXxSjECmJoTVL6SJ27uzYrXHOWUiqKaMTK0gW6LfJXJrsfQ%40mail.gmail.com . -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sympy+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/sympy/b470b427-aedb-44b8-993b-97f71e1d6b8dn%40googlegroups.com.
