If I put it as (x^2)^(1/5) it works fine.
From: sympy@googlegroups.com <sympy@googlegroups.com> On Behalf Of Paul Royik Sent: Wednesday, December 11, 2024 8:15 PM To: sympy <sympy@googlegroups.com> Subject: [sympy] Real-valued root I try to use the bridge between sympy and numpy, namely, the lambdify function. It looks ok, but there is an issue when I try to calculate the values of x^(2/5) on the interval [-5,5]. Of course, for negative x, the value is nan, because, I guess, the root is not real-valued. How to make it real-valued? Thank you. -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sympy+unsubscr...@googlegroups.com <mailto:sympy+unsubscr...@googlegroups.com> . To view this discussion visit https://groups.google.com/d/msgid/sympy/02b3834f-d2ba-4767-a28e-4b6ae1355906n%40googlegroups.com <https://groups.google.com/d/msgid/sympy/02b3834f-d2ba-4767-a28e-4b6ae1355906n%40googlegroups.com?utm_medium=email&utm_source=footer> . -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sympy+unsubscr...@googlegroups.com. To view this discussion visit https://groups.google.com/d/msgid/sympy/006e01db4c14%24ad823490%2408869db0%24%40gmail.com.
