Putting image paths in a database would only work if you know beforehand
the path and name of all the images you want displayed (not to mention
the unreasonable overhead of updating that database for additional
images added or existing image files renamed later on). What you would
want, if David's assumption is correct, is to automatically read the
names of all image files contained in a given path location at the time
of script execution , and then loop through each of the names and
display the appropriate html img tag for each of these images.
IMHO, you could adopt for a simpler approach by using the concept of
<google_for_more_info>directory browsing in php</google_for_more_info>.
The pseudo code of one possible way (among several others) would be
something like this (hopefully assuming you are not stuck in a chrooted
web jail).
function displayallimages($imagepathlocation) {
$listoffiles = system("ls " . $imagepathlocation);
//filter $listoffiles to contain an array list of only valid image
files based on allowable image file extensions
foreach($listoffiles as $imgfile)
echo '<img src='.$imgepathlocation.'/'.$imgfile.'/>'; //make
sure the image path here is relative to the document root of the web
server
}
Or at least I think that is one way to do it.
________________________________
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of Susan Shemin
Sent: Thursday, October 25, 2007 7:26 PM
To: NYPHP Talk
Subject: Re: [nyphp-talk] opening files
Just adding on David's answer -- put the name/path of the image in a
variable in your database. I've done it because the name of the image
matches the name of the record entry so it's easy to locate the correct
image to display through a query. Let's say the business is Susan so my
logo for the business is named susan.jpg which I can easily locate in a
query.
susan
----- Original Message ----
From: David Krings <[EMAIL PROTECTED]>
To: NYPHP Talk <[email protected]>
Sent: Thursday, October 25, 2007 3:37:01 PM
Subject: Re: [nyphp-talk] opening files
selyah wrote:
> Hello Folks:
> I am still relatively new with php and am enjoying it very much. I am
> creating a html script to show images on a page. instead of creating
a
> source image for all of the images, i would like to incorporate a php
> script that would "go" to the file location where all of the images
are
> and display them. I wrote a script but it does not work. Any help or
> ideas ? thanks
> new guy
You'd need to provide some code samples for us to give you some advice.
Also,
what do you consider the difference between "creating a source image"
and "go
to the location where all of the images are and display them"? I'd
establish a
place where all images are (as appears to be given in your case), then
write a
script that creates pages with <img> tags that point to the image in the
specific location.
I created and still work on a very similar system with a database
backend that
allows for quite complex searches and a bunch of other stuff.
Basically, you need to tell us what you did so that we can tell you what
you
did wrong.
David
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