On Thu, Dec 3, 2009 at 1:05 PM, Steve Bennett <stevag...@gmail.com> wrote:
> Let's take this situation:
>
>        B
>        |
> A==============C
>
> You're going from A to B. I'm saying that the router doesn't attempt to make
> the turn because the way A-C is marked as divided=median, and there's
> nothing at the intersection to overrule that. If left turns are possible
> there, then the junction should be marked as a gap, or there should be a
> section of non-divided at that point.

So if I decide to split AC for whatever reason, I've just broken the routing?

Relations aren't that hard.  Not nearly hard enough to justify
something like this.  IMHO.

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