On Sat, Dec 08, 2001 at 10:22:15PM -0800, Guy Harris wrote:
>       3) breaks anything you notice?

Of course, one headache is that unless an expression uses a significant
number of scratch locations, the additional "free_reg()" won't change
the code it generates, as registers don't get reused until the
allocator's current register number wraps around, so problems might not
show up except in sufficiently complex expressions.
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