>> [...set -e vs shell functions...]
> Does this achieve what you want?
> #!/bin/sh
> set -e
> f() {
> echo foo
> false
> echo bar
> }
> f
> [ $? ] || echo baz
> echo buzz
I'm not the original poster, but it does not achieve what I would
expect, which is
foo
baz
buzz
That is, I would expect/want -e to cause the function to return showing
failure. Instead, it either does nothing or takes down the whole
shell.
This does achieve it, not surprisingly, but it's an ugly kludge; I
would say that neither the nested sh nor the nested set -e should be
necessary:
set -e
f() {
sh -c '
set -e
echo "foo $-"
false
echo bar
'
}
f || echo baz
echo buzz
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