> That equation only holds if the probability of failure for each block > are independent from one another which is certainly not the case.
Could you explain, exactly, why failure of a piece of data is not independent from failure of another block? Unless nodes keep tabs on individual blocks of data (as referenced from index blocks, or whatever), failure of a single chunk of data is in no way related to failure of another chunk of data. --delta407 _______________________________________________ freenet-tech mailing list [EMAIL PROTECTED] http://lists.freenetproject.org/mailman/listinfo/tech
