Bug in gcc 3?

[Tim van der Molen]

I'm running i386 -current of 13 May and ran into surprising behaviour
from gcc. Consider the following code snippet:

        int i;

        i = 1;
        if (i += 1 == 2)
                printf("%d; should be 2\n", i);

        i = 1;
        if ((i += 1) == 2)
                printf("%d; should be 2\n", i);

The output is:

        1; should be 2
        2; should be 2

It seems gcc parses the += statement wrongly: "a += b == c" should be
interpreted as something like "(a = a + b) == c", but instead gcc seems
to interpret it as "a = (a + b == c)". That would explain why i equals 1
in the first line of output.

Would this be a bug in gcc or am I overlooking something?

Regards,
Tim