> On 5 Sep 2016, at 17:39, Ali H. Fardan <[email protected]> wrote:
>
> and why is he telling me this? I just said if the destination is a
> pointer to char, how would a function automagically allocate a size
> for it?
its not a pointer to a char, its a pointer to a char pointer:
as per the man page:
int
asprintf(char **ret, const char *format, ...);
dlg
>
> -------- Original Message --------
> Subject: Re: mount(8): strlen + malloc + snprintf == asprintf
> Date: 2016-09-05 10:36
> From: "Michael W. Bombardieri" <[email protected]>
> To: "Ali H. Fardan" <[email protected]>, Otto Moerbeek <[email protected]>
> Cc: David Gwynne <[email protected]>, tech <[email protected]>,
> [email protected]
>
> FWIW the reply seemed like a proper statement to me.
>
> The manual page for asprintf() doesn't explain its internals. Do you expect
> someone to give you a summary of asprintf() internals? I don't see why they
> should.
>
> On 2016-09-05 3:15 PM, Ali H. Fardan wrote:
>> On 2016-09-05 08:52, Otto Moerbeek wrote:
>>> On Mon, Sep 05, 2016 at 08:05:40AM +0300, Ali H. Fardan wrote:
>>>> On 2016-09-05 08:01, David Gwynne wrote:
>>>> > > On 5 Sep 2016, at 12:13, Ali H. Fardan <[email protected]> wrote:
>>>> > >
>>>> > > You can't specify a buffer size in asprintf() therefore, it is not
>>>> > > secure,
>>>> > > you can see that snprintf() does write to the `i` bytes to the buffer
>>>> >
>>>> > asprintf allocates the memory it needs to write to, unlike snprintf
>>>> > which requires a preallocated buffer.
>>>> when the destination is a pointer to a char, and the passed argument is a
>>>> memory address, how is it supposed to determine the correct buffer size?
>>>> Raiz
>>> asprintf uses the internals of the printf family of functions. Look in
>>> src/lib/libc/stdio for all the details.
>>> -Otto
>> If you can read my statement and reply with a proper statement,
>> I'd appreciate it.
>> Raiz
>
