Hi sini-Kit
I think the keep[] operator should do the trick: <$list
filter="[list[!!list1]keep{!!list2}keep{!!list3}]"/>
You will find the keep[] operator in the version of the x-listops filters
from here <http://listops.tiddlyspot.com/>.
regards
On Thursday, 4 February 2016 16:42:26 UTC+2, sini-Kit wrote:
>
> I have 3 lists:
> list1[1 2 3 4 5 6 7 8]
> list2[4 5 6 7 8]
> list3[1 5 8]
>
> the result of intersection must be list_int[5 8]
> in other words I want to find items which all lists have - it is 5 and 8.
>
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