Hi Bruce, wow, haven't done that math since about 1987.. I remember now. How about Cs? Seems more aggressive. bye, Said In a message dated 4/23/2008 23:52:31 Pacific Daylight Time, [EMAIL PROTECTED] writes:
[EMAIL PROTECTED] wrote: > Hi Bruce, > > last chemistry/physics class is a while back :) I guess a half life of 50 > Billion years means it's not really radiating much? > > No problem with Cesium then either, I guess the radiation levels must be > really really low? > > thanks, > Said > Said Calculating the number of atoms that decay per second in a particular sample is almost trivial: Divide the mass of the sample (in grams) by the atomic weight, multiply the result by Avogadro's number and then divide by the number of seconds in 5E10 years. Result for a 10gm sample of Rb87 No of atoms present ~ 6.02E23 x 10/85 ~ 7E22 No of seconds in 5E10 years ~ 1.5E18 Thus number atoms in the sample decaying per second ~47,000. Equivalent electron current ~ 7.6fA. One saving grace is that beta particles (electrons) are essentially stopped by a piece of paper, just dont eat the stuff. Bruce _______________________________________________ time-nuts mailing list -- time-nuts@febo.com To unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts and follow the instructions there. **************Need a new ride? Check out the largest site for U.S. used car listings at AOL Autos. (http://autos.aol.com/used?NCID=aolcmp00300000002851) _______________________________________________ time-nuts mailing list -- time-nuts@febo.com To unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts and follow the instructions there.
