Problem is one period of 32768 is not a multiple of 100nS (one period of 10 MHz) so that won't work. Maybe there is a common denominator and it may be possible to generate an average 32768 periods over one second, even though all periods may not be equal.
Didier KO4BB ---- Mike S <[EMAIL PROTECTED]> wrote: > At 10:09 AM 7/23/2008, Max Skop wrote... > >How does one get a 32.768KHz signal from our 10MHz reference. > >There does not appear to be a nice divide ratio to do this. > > I've thought about this too. It seems the simple way would be to clock > a PIC with the 10 MHz, then use loops to produce the 32768 Hz. It's > easier than it seems once you realize that phase noise doesn't really > matter in this application - duty cycles don't need to be exactly 50%, > etc. > > > _______________________________________________ > time-nuts mailing list -- time-nuts@febo.com > To unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts > and follow the instructions there. _______________________________________________ time-nuts mailing list -- time-nuts@febo.com To unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts and follow the instructions there.