Not quite. You need &buf[0]
buf is a pointer to the array. (first element)
&buf is a pointer to that pointer.
&buf[0] is a pointer to the first element of the array.
Hal, try the following with your C compiler...
#include <stdio.h>
void main ()
{
char buf[100] = { 3,1,4,1,5 };
printf("0x%.8lX\n", buf);
printf("0x%.8lX\n", &buf);
printf("0x%.8lX\n", buf[0]);
printf("0x%.8lX\n", &buf[0]);
}
And see if your results and intuition agree.
0x0012FF1C
0x0012FF1C
0x00000003
0x0012FF1C
/tvb
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