Hal, Here are the results I got using your suggestion. The numbers may be a bit different than last night as I'm not sure I'm using the same cable.
A+, B+ = 18.9 ns A-, B- = 19.4 ns Obviously there is some difference in delay between the A and B channels. Otherwise, the two numbers would have been identical - correct? If I take the average of the two readings, I get 19.05 ns, which is more precise than the readings I'm taking. I'm rounding to the nearest 0.1 ns on the readings. A+, B- = 5014.6 ns A-, B+ = 5023.5 ns If I take the average of these two readings and subtract out the 5 us for 1/2 period of the 100 KHz square wave, if get 19.15 ns. This agrees very closely with the above average. I haven't looked at the service manual for the 5328A yet, so I don't know if I even have the proper equipment to attempt a calibration. In the mean time, would you say that taking the average of the first two readings is a valid method? Joe Gray W5JG On Sun, Apr 3, 2011 at 7:18 PM, Hal Murray <hmur...@megapathdsl.net> wrote: > > How about a square wave? Start on one edge, stop on the next cycle. > > You can play with start on rising edge, stop on falling and the reverse. > They should add up to the total. _______________________________________________ time-nuts mailing list -- time-nuts@febo.com To unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts and follow the instructions there.