We are all time nuts, so there's an obvious answer: What you do, is raise the GPS up to a height the same as the cable length. You then drop it, measure the time until it hits the ground, and use d = 0.5 a * t * t to calculate d. Then you correct for the velocity factor.
Tim N3QE On Wed, Jun 29, 2016 at 3:28 PM, Hal Murray <hmur...@megapathdsl.net> wrote: > > bro...@pacific.net said: > > At one point they were looking into making a GPS time receiver where the > > cable length calibration would be built-in. > > How would you do that? > > The obvious way is to compare the time you get with a known-good time, but > if > you had that, why would you want this new GPS with an unknown cable length. > > You might be able to do it by measuring the DC drop. Getting enough > accuracy > seems tough. > > > -- > These are my opinions. I hate spam. > > > > _______________________________________________ > time-nuts mailing list -- time-nuts@febo.com > To unsubscribe, go to > https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts > and follow the instructions there. > _______________________________________________ time-nuts mailing list -- time-nuts@febo.com To unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts and follow the instructions there.
