Hello Christian,
Am 16.02.2013 12:04, schrieb Christian Jullien:
tcc_define_symbol(s, "__STDC_VERSION__", "199901L");
This define pretends it is ISO/IEC 9899:1999 (E)
Strictly speaking that's optimistic, because it also depends on the C
library on which tcc has no influence (some embedded C libs can be
configured to not support wchar for instance). But in your case it's
simply an error on your part.
Because __STDC_VERSION__ is set to 199901L
This code should be legal:
It's legal, but doesn't do what you want:
int main()
{
When a program is started stdout/err/in have no orientation yet. The
first input/output operation determines which orientation it gets ...
#if defined(__STDC_VERSION__) && (__STDC_VERSION__ >= 199901L)
wchar_t* s = L"ABCDEFGHIJKLMNOPQRSTUVWXYZ";
char* p = (char*)s;
printf("%x %x %x %x\n", p[0],p[1],p[2],p[3]);
... and printf is byte-oriented, so stdout will from now on be
byte-oriented, and the string is output...
printf("%x %x %x %x\n", p[4],p[5],p[6],p[7]);
... stdout is byte-oriented, printf is byte-oriented, so the string is
output ...
wprintf(L"Hello World\n");
... and this doesn't work, because stdout is byte-oriented, but wprintf
requires a stream that isn't byte-oriented. If you had checked for
errors you would have seen one. Once a stream has an orientation it
can't be switched anymore. Remove the printf's and leave only wprintf
and it works. Alternatively if you want to output wide characters on a
byte-oriented stream use printf and %ls. For the whole background see
fwide(3) and wprintf(3).
Ciao,
Michael.
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