Concretely: Are there reservations towards replacing

> When a DTLS implementation receives a handshake message fragment
> corresponding to the next expected handshake message sequence number, it
> MUST buffer it until it has the entire handshake message.

by

> When a DTLS implementation receives a handshake message fragment
> corresponding to the next expected handshake message sequence number,
> it is RECOMMENDED that it buffers it until it has the entire handshake 
> message.

in the DTLS 1.3 draft?

Happy to file a PR if not.

Regards,
Hanno
________________________________
From: TLS <tls-boun...@ietf.org> on behalf of Hanno Becker 
<hanno.bec...@arm.com>
Sent: Saturday, November 6, 2021 8:18 AM
To: Achim Kraus <achimkr...@gmx.net>
Cc: tls@ietf.org <tls@ietf.org>
Subject: Re: [TLS] DTLS 1.2 and 1.3: HS message reassembly prior to processing

Hey Achim,

Thanks for the quick reply!

Actually, for TLS, you can do the same: Process handshake messages
piece by piece (ordered, this time), without full reassembly. I'm
not aware that the TLS spec forbids that, or does it?

For Post-Quantum Crypto, streaming implementations of schemes
with very large key materials are a thing, see e.g. SPHINCS or McEliece [1].
However, those are only of value for (D)TLS if the (D)TLS stack forwards data
to the handshake layer prior to full reassembly -- again, both in TLS and DTLS.

You're right that in DTLS the situation is even harder, because
fragments might be received out of order. But that doesn't mean
there's no way of potentially processing them out of order -- it very
much depends on the data. E.g. if you receive a huge matrix
which you'd like to perform a matrix-vector multiplication with,
you can do that entry by entry -- so long as you know the offset
of the data you received, which you do of course.

Note also that in the context of Post-Quantum Crypto, we're sometimes
talking about key material >100Kb - this is an issue for MCUs.

I think a MUST like this should have a justification. If there's none, then
IMO it should be left out for the benefit of implementation flexibility.

Cheers,
Hanno

[1]:

Johannes Roth and Evangelos Karatsiolis and Juliane Krämer

"Classic McEliece Implementation with Low Memory Footprint",
https://eprint.iacr.org/2021/138,
Cryptology ePrint Archive: Report 2021/138 - Classic McEliece Implementation 
with Low Memory Footprint - IACR<https://eprint.iacr.org/2021/138>
Cryptology ePrint Archive: Report 2021/138. Classic McEliece Implementation 
with Low Memory Footprint. Johannes Roth and Evangelos Karatsiolis and Juliane 
Krämer
eprint.iacr.org


________________________________
From: Achim Kraus <achimkr...@gmx.net>
Sent: Saturday, November 6, 2021 7:36 AM
To: Hanno Becker <hanno.bec...@arm.com>
Cc: tls@ietf.org <tls@ietf.org>
Subject: Re: [TLS] DTLS 1.2 and 1.3: HS message reassembly prior to processing

Hi Hanno,

 > Can someone explain the underlying rationale?

I can only guess, that this makes the processing of the handshake
messages equal to TLS. So it's separating the layers (record layer -
handshake layer).

 > It seems that in the context of very large key material or certificate
 > chains (think e.g. PQC), gradual processing of handshake messages
 > (where possible) is useful to reduce RAM usage.
 > Is there a security risk in doing this?

I'm not sure, if such an approach really pays off. Consider, that
sometimes the fragments may be reordered or single fragments are
missing. Under such conditions, collecting the fragments is a solution,
which makes receiving the complete message more probable.
For me, if someone decides to go with x509, then please provide the RAM.
That RAM may only be used temporary, later it may be used for
application payload processing. So, I don't think this should be really
an issue.

 > It would also be useful for stateless handling of fragmented
 > ClientHello messages. I'm sure this was discussed before but
 > I don't remember where and who said it, but a server implementation
 > could peek into the initial fragment of a ClientHello, check if it
 > contains a valid cookie, and if so, allocate state for subsequent full
 > reassembly. That wouldn't be compliant with the above MUST, though,
 > as far as I understand it.

How do you want to calculate the cookie. According:

https://datatracker.ietf.org/doc/html/rfc6347#section-4.2.1

Cookie = HMAC(Secret, Client-IP, Client-Parameters)

So, which Client-Parameters are included?
For me, stateless processing would require to challenge the first
fragment (0) only, though otherwise, I can't see, how that could work
stateless.
If the cookie is build only for the first fragment, you must ensure,
that the Client-Parameters, which may be shifted by the cookie to the
next fragment, are excluded from the cookie's Client-Parameters,
otherwise you will not be able to do a stateless check of first fragment
with cookie.

But that all seems for me to be not mentioned nor intended by RFC6347.
Therefore I would recommend, to use less Client-Parameters to make the
ClientHello small. That's one good reason for RFC7252 to define a
mandatory set, clients can rely on.

best regards
Achim Kraus

Am 05.11.21 um 20:14 schrieb Hanno Becker:
> Hi all,
>
> Both DTLS 1.2 and DTLS 1.3 mandate:
>
>  > When a DTLS implementation receives a handshake message fragment
> corresponding to the next expected handshake message sequence number, it
> MUST buffer it until it has the entire handshake message.
>
> Can someone explain the underlying rationale?
>
> It seems that in the context of very large key material or certificate
> chains (think e.g. PQC), gradual processing of handshake messages
> (where possible) is useful to reduce RAM usage.
> Is there a security risk in doing this?
>
> It would also be useful for stateless handling of fragmented
> ClientHello messages. I'm sure this was discussed before but
> I don't remember where and who said it, but a server implementation
> could peek into the initial fragment of a ClientHello, check if it
> contains a valid cookie, and if so, allocate state for subsequent full
> reassembly. That wouldn't be compliant with the above MUST, though,
> as far as I understand it.
>
> Thanks!
> Hanno
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