DO NOT REPLY TO THIS EMAIL, BUT PLEASE POST YOUR BUG RELATED COMMENTS THROUGH THE WEB INTERFACE AVAILABLE AT <http://nagoya.apache.org/bugzilla/show_bug.cgi?id=5224>. ANY REPLY MADE TO THIS MESSAGE WILL NOT BE COLLECTED AND INSERTED IN THE BUG DATABASE.
http://nagoya.apache.org/bugzilla/show_bug.cgi?id=5224 Can't declare listeners in web.xml Summary: Can't declare listeners in web.xml Product: Tomcat 4 Version: 4.0 Final Platform: PC OS/Version: Windows NT/2K Status: NEW Severity: Major Priority: Other Component: Catalina AssignedTo: [EMAIL PROTECTED] ReportedBy: [EMAIL PROTECTED] According to the Servlet 2.3 SPEC, this is a correct specification for a listener: <web-app> <display-name>MyListeningApplication</display-name> <listener> <listener-class>com.acme.MyConnectionManager</listener-class> </listener> <listener> <listener-class>com.acme.MyLoggingModule</listener-class> </listener> <servlet> <display-name>RegistrationServlet</display-name> ...etc </servlet> </web-app> However, when I do this in my web.xml, I get this error on startup: Starting service Tomcat-Standalone Apache Tomcat/4.0 PARSE error at line 11 column -1 org.xml.sax.SAXParseException: Element "web-app" does not allow "listener" here. Starting service Tomcat-Apache Apache Tomcat/4.0 What is the correct way to declare a listener? -- To unsubscribe, e-mail: <mailto:[EMAIL PROTECTED]> For additional commands, e-mail: <mailto:[EMAIL PROTECTED]>
