Paul,
If the file is in a JAR you can generate a URL to access it.
either something along the lines of
ServletContext context = getServletConfig().getServletContext();
URL url = context.getResource("/path/file.xml");
or alternatively using the class loader
URL url = getClass().getResource("/path/file.xml");
Best regards
Robert
-----Original Message-----
From: Paul Wallace [mailto:[EMAIL PROTECTED]
Sent: 07 September 2005 07:51
To: Tomcat Developers List
Subject: io.File relative path constructor
Hi,
A should-be easy one - I do not wish to define an absolute path
to a File as it will packaged in a JAR, therefore its path will change.
How do I construct a File relative to my src root, something like File
file = new File("/path/myFile.xml");? I tried passing in a URL, URI but
am getting:
Exception in thread "main" java.lang.IllegalArgumentException: URI is
not hierarchical
when I jar and run it. Am using Win XP + Java 1.5.
Thanks
Paul.
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