RE: ErrorPage.jsp - how to get the address of the offending page?

[Frank Zammetti]

Try looking for the attribute "request_uri" without the whole class 
specification before it... it still may not be available in Tomcat 3.x, and 
I've seen reference to looking it up the way you are, but I'm fairly certain 
that attribute is present in current Tomcat versions as just request_uri, 
and I'm wondering if maybe it was in that version too.


From: Dola Woolfe <[EMAIL PROTECTED]>
Reply-To: "Tomcat Users List" <[EMAIL PROTECTED]>
To: Tomcat Users List <[EMAIL PROTECTED]>
Subject: RE: ErrorPage.jsp - how to get the address of the offending page?
Date: Tue, 1 Jun 2004 08:47:07 -0700 (PDT)
So am I out of luck or is there an alternative way?
--- Mike Curwen <[EMAIL PROTECTED]> wrote:
> Yes, that would be the reason.  From the
> corresponding section of the
> spec for servlet 2.2:
>
> If the location of the error handler is a servlet or
> a JSP, the
> following
> request attributes can be set:
> . javax.servlet.error.status_code
> . javax.servlet.error.exception_type
> . javax.servlet.error.message
>
> So you'd need tomcat 4 and above for
> javax.servlet.error.request_uri
>
>
> > -----Original Message-----
> > From: Dola Woolfe [mailto:[EMAIL PROTECTED]
> > Sent: Tuesday, June 01, 2004 3:28 AM
> > To: [EMAIL PROTECTED]
> > Subject: Re: ErrorPage.jsp - how to get the
> address of the
> > offending page?
> >
> >
> >
> > > Does the request attribute
> > > javax.servlet.error.request_uri  suit your needs
> ?
> > > (from the servlet spec, SRV.9.9.1)
> >
> > Actually returns null. I'm using Tomcat 3; Could
> that
> > be the reason?
> >
> > Here's my snippet:
> >
> > <%@ page isErrorPage="true"%>
> > <%
> >
>
System.out.println(request.getAttribute("javax.servlet.error.r
> > equest_uri"));
> >
> > %>
> >
> >
> >
>
>
>
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