In Tomcat 3.2.x you can specify which directory
you want tomcat to pick up your servlet.
In the distribution server.xml for instance:
<Context path="/examples"
docBase="webapps/examples"
crossContext="false"
debug="0"
reloadable="true" >
</Context>
states that the servlets/jsp pages are found under
$TOMCAT_HOME/webapps/examples.
So you can create your own context:
<Context path="/myservlet"
docBase="webapps/myservlet"
crossContext="false"
debug="0"
reloadable="true" >
</Context>
And you have to add the WEB-INF directory underneath
the webapps/myservlet directory and populate that with
a web.xml (the deployment descriptor for your servlet)
and also add a classes directory to put your classes
in there. For the first go-around, put your classes in
the default package (i.e., no package stmt).
Hope this helps.
-Ganesh
Hope this helps.
-Ganesh
--- [EMAIL PROTECTED] wrote:
> I got a chance to look at server.xml. And it is
> almost like apache, however
> when I type http://127.0.0.1/path to a servlet, I
> get the page couldn't be
> find error message. I don't think the connection is
> even being made. I looked
> over the server.xml regarding "context" to see the
> directories where the
> application files are to be put, and I also looked
> at the virtual host and
> the virtual host says to type url
> http://127.0.0.1/examples/where the servlet
> is to be find and still nothing . Anyone has any
> suggestions.......
>
>
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