Thanks! That did the trick. Now, I'm getting NULL's in getting the request
parameters in my serlvet. I'll have to look at that a little more.
------Original Message------
From: Michael Wentzel <[EMAIL PROTECTED]>
To: "'[EMAIL PROTECTED]'" <[EMAIL PROTECTED]>
Sent: April 4, 2001 2:08:46 PM GMT
Subject: RE: web.xml problem?
> I'm using tomcat321 on NT4.0.
> I have a simple login page that I'm trying to call my servlet
> to do some
> processing on the request parameters. But, Tomcat cannot find
> my servlet.
> See the details below. Any suggestions?
>
> Here are my paths:
>
> c:\opensource\tomcat321\webapps\TrainingPlansRepository\jsp\Login.html
> c:\opensource\tomcat321\webapps\TrainingPlansRepository\web-in
> f\classes\born\servlets\LoginController.class
>
> Here is a part of my web.xml:
>
> <web-app>
> <servlet>
> <servlet-name>
> LoginController
> </servlet-name>
> <servlet-class>
> born.servlets.LoginController
> </servlet-class>
>
> <servlet-mapping>
> <servlet-name>
> LoginController
> </servlet-name>
> <url-pattern>
> /TrainingPlansRepository/born/servlets/LoginController
> </url-pattern>
> </servlet-mapping>
>
> Here is the line that matters in my Login.html:
> <FORM METHOD=POST ACTION="born/servlets/LoginController">
>
> Here is the resulting error msg in Netscape:
> Not Found (404)
>
> Original request:
> /TrainingPlansRepository/jsp/born/servlets/LoginController
>
> Not found request:
> /TrainingPlansRepository/jsp/born/servlets/LoginController
>
change your url pattern to
<url-pattern>
LoginController
</url-pattern>
or
<url-pattern>
/servlet/LoginController
</url-pattern>
if you really want the servlet path in there.
and then change your ACTION to ../LoginController or
.../servlet/LoginController
appropriately.
---
Michael Wentzel
Software Developer
Software As We Think - http://www.aswethink.com
mailto:[EMAIL PROTECTED]
- Punisher of those who cannot spell dumb!
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