Hi Please help. Im trying to run tomcat4.05b under Win ME. Having installed Jdk1.3.1 into c:\jdk1.3.1 and unpacked the Tomcat 4.05b version into the default C:\jakarta-tomcat-4.0-b5 folder. Then having modified the Environment settings such that: C:\WINDOWS>SET COMSPEC=C:\WINDOWS\COMMAND.COM C:\WINDOWS>SET windir=C:\WINDOWS C:\WINDOWS>SET winbootdir=C:\WINDOWS C:\WINDOWS>SET PROMPT=$p$g C:\WINDOWS>SET TEMP=C:\WINDOWS\TEMP C:\WINDOWS>SET TMP=C:\WINDOWS\TEMP C:\WINDOWS>SET PATH=C:\PROGRA~1\MICROS~1\OFFICE;C:\WINDOWS;C:\WINDOWS\COMMAND;"C:\Program Files\Mts" C:\WINDOWS>SET JAVA_HOME=c:\jdk1.3.1 C:\WINDOWS>SET CLASSPATH=c:\jdk1.3.1\lib C:\WINDOWS>SET TOMCAT_HOME=C:\jakarta-tomcat-4.0-b5 C:\WINDOWS>SET JAXP_HOME=C:\JDK1.3.1\JAXP1.1 C:\WINDOWS>SET SHELL=c:\windows\command.com /P /E:8192 is returned by a 'command /p' entered at the command prompt When I invoke the startup.bat file, all i get is : out of environment space out of environment space out of environment space out of environment space out of environment space using CLASSPATH: bad command or filename Returned in the command prompt window?? I have upped the /E: value to the max 32786 value and still get this display?? please advise. Phil K