Incidentally, the value will be null if you access the servlet URL directly, without an intervening page.
John > -----Original Message----- > From: Turner, John [mailto:[EMAIL PROTECTED]] > Sent: Wednesday, August 28, 2002 3:31 PM > To: 'Tomcat Users List' > Subject: RE: need to find out the URL of the page that sent > the request > > > > No, it's a HTTP spec. > > Here's my chance to correct Charlie's correction of my > original post! :) > > I think it should be: > > request.getHeader("referer"); (note lower case "r") > > If you want to see an example, check the tomcat examples, the > servlet is > called RequestHeaderExample and the source code should be > available in the > examples directory. > > John > > > -----Original Message----- > > From: Peter Choe [mailto:[EMAIL PROTECTED]] > > Sent: Wednesday, August 28, 2002 3:26 PM > > To: Tomcat Users List > > Subject: RE: need to find out the URL of the page that sent > > the request > > > > > > thanks. but when i tried to do request.getHeader("Referer") > > it just gave > > me null. is this browser specific? > > > > Peter Choe > > > > At 03:12 PM 8/28/2002, you wrote: > > > > >You're right, my bad. > > > > > >John > > > > > -- > To unsubscribe, e-mail: <mailto:[EMAIL PROTECTED]> For additional commands, e-mail: <mailto:[EMAIL PROTECTED]> -- To unsubscribe, e-mail: <mailto:[EMAIL PROTECTED]> For additional commands, e-mail: <mailto:[EMAIL PROTECTED]>
